I need help pls 1 - 8 thanks

Mathematics

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

1. 0.5454

2. 8

3. 0.6785

4. 1.1428

5. 6

6. 1.5

7. 1.75

8. 1.6666

Step-by-step explanation:

calculator :)

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Please‼️help me<br>Myanmar Grade7

cricket20 [7]

Answer:

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5 0

2 years ago

Math question down below

kramer

X + 4/5 = 11
x = 11 - 4/5
x = 55/5 - 4/5
x = 51/5 or 10 1/5

or u can do it this way..
x + 4/5 = 11.....multiply everything by common denominator of 5
5x + 4 = 55
5x = 55 - 4
5x = 51
x = 51/5 or 10 1/5

7 0

3 years ago

The length of a rectangle is nine inches more than its width. Its area is 486 square inches. Find the width and length of the re

Elan Coil [88]

Answer:

width: 18 in
length: 27 in

Step-by-step explanation:

The relations between length (L) and width (W) are ...

W +9 = L

LW = 486

Substituting gives ...

(W+9)W = 486

W^2 +9W -486 = 0 . . . put in standard form

(W +27)(W -18) = 0 . . . . factor

W = 18 . . . . the positive solution

The width of the rectangle is 18 inches; the length is 27 inches.

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<em>Comment on factoring</em>

There are a number of ways to solve quadratics. Apart from using a graphing calculator, one of the easiest is factoring. Here, we're looking for factors of -486 that have a sum of 9.

486 = 2 × 3^5, so we might guess that the factors of interest are -2·3² = -18 and 3·3² = 27. These turn out to be correct: -18 +27 = 9; (-18)(27) = -486.