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3 years ago

Explain how to change a mixed fraction into an improper fraction.

Mathematics

2 answers:

Solnce55 [7]3 years ago

7 0

Answer:

To do this you will need to multiply the denomenator by the whole number and then add the numerator to that number. After you get that the new numerayoer is the big number and the denomentapr stays the same.

Step-by-step explanation:

2 1/2

5/2

Pie3 years ago

5 0

Answer:

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

Step-by-step explanation:

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-3w² + x2 – 5W + 4x²

Mnenie [13.5K]

Answer:

-3w^2+5x^2-5w

Step-by-step explanation:

4 0

3 years ago

Solve each equation by graphing the related function. if the equation has no real-number solution, write no solution. 3x^2=0

Artist 52 [7]

3x^3=0
the only possible answer is x=0

factor
3(x^3)=0
x^3=0
x=0

C

4 0

4 years ago

Read 2 more answers

Which of these is the algebraic expression for "five more than the product of ten and some number?"

Vladimir79 [104]

Answer:

10 + 5x hope it helps

8 0

3 years ago

Find the indicated probability. Round to three decimal places. The participants in a television quiz show are picked from a larg

Arturiano [62]

Answer:

0.033

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ (1−p)ⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Here, p = 0.5, q = 0.5, and n = 11.

We need to find P when r is 0, 1, and 2, then add up the results to get the total probability.

r = 0:

P = ₁₁C₀ (0.5)⁰ (0.5)¹¹⁻⁰

P ≈ 0.0005

r = 1:

P = ₁₁C₁ (0.5)¹ (0.5)¹¹⁻¹

P ≈ 0.0054

r = 2:

P = ₁₁C₂ (0.5)² (0.5)¹¹⁻²

P ≈ 0.0269

Therefore, the total probability is:

P = 0.0005 + 0.0054 + 0.0269

P = 0.0328

Round to the thousandths place, the probability is 0.033.

3 0

3 years ago

Questions (no partial grades if you don't show your work) 1. In a group of 6 boys and 4 girls, four children are to be selected.

mariarad [96]

Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = $^{6}C_{1}\times^{4}C_{3}=6\times4$ =24

2 Boy and 2 girls= $^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90$

3 Boys and 1 girl = $^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80$

4 Boys = $^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15$

Now total number of ways = 24 + 90 + 80 + 15 = 209

7 0

3 years ago