If Heidi only gets paid when she is talking to clients, she will be working
... 9 × (40 min/60 (min/h)) = 6 h
per day.
Her $2.00 difference in pay per hour will result in a difference in pay per day of
... $2.00/h × 6 h/day = $12/day
Company B will pay Heidi $12 more for a day's work.
Answer:
36=3*2*1*6
36=6*6
Step-by-step explanation:
_/36=6
Hope this helped :)
1.) 1/3 & 4/12
2.) 2/5 & 8/20
3.) 6/16 & 9/24
4.) 6/10 & 9/15
Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0409 = 4.09% probability that, from a simple random sample of 300 adults in the county, less than 50% would say they believe that gardening should be part of the school curriculum.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample proportions for a proportion p in a sample of size n has

In this problem:
- The proportion is of 55%, hence

- The sample has 300 adults, hence

Then, the <u>mean and the standard error</u> are given by:


The probability is the <u>p-value of Z when X = 0.5,</u> hence:

By the Central Limit Theorem



has a p-value of 0.0409.
0.0409 = 4.09% probability that, from a simple random sample of 300 adults in the county, less than 50% would say they believe that gardening should be part of the school curriculum.
A similar problem is given at brainly.com/question/25800303
Answer:
7(−x−1)(x−3)
Step-by-step explanation: