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2 years ago

An expression is shown. 1/6 + 1/6 What is the value of the expression?

Mathematics

2 answers:

Amiraneli [1.4K]2 years ago

4 0

Answer:

1/3 in simple

Step-by-step explanation:

1/6 +1/6 = 2/6= 1/3

stealth61 [152]2 years ago

4 0

1/3 is the correct answer

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Divide. Write your answer in lowest terms. 3/4 divided by 6/1

Trava [24]

Since dividing fractions are not possible, you must first find the reciprocal of 6/1 which is 1/6. And the equation would be written as 3/4*1/6. Cross cancel the 3 and 6 leaving 1/4*1/2=1/8. Thus, your answer is lowest terms is, 1/8.

8 0

2 years ago

Pls helpppp I give brainliest <3

Pavel [41]

Answer:

9cups of dried split peas

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Step-by-step explanation:

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2 1/4 x 4 = 9

2 x 4 = 8

3/4 x 4 = 3

1 x 4 = 4

2 x 4 = 8

6 0

2 years ago

What is the product of 2 numbers of 1 2 3 4 5 6 10 20 30

Zanzabum

Answer:

ekena la pernina de la abobo Kot Sa Rita kolos talas 8

5 0

2 years ago

Solve the system.

gtnhenbr [62]

X = y + 11

2x + y = -2
2(y + 11) + y = -2
2y + 22 + y = -2
3y + 22 = -2
3y = -24
y = -8

x = y + 11
x = -8 + 11
x = 3

Solution set {3, -8} (C)

8 0

3 years ago

Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

1 year ago