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Ivanshal [37]
3 years ago
13

Whats the answer? And step by step?

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

Answer:

one answer

Step-by-step explanation:

set the equal to each other and you get one answer

2x+6= -3x -4

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Someone please help me!!!
devlian [24]

Answer:

sorry cant help

Step-by-step explanation:

6 0
3 years ago
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Evaluate the factorial.<br> 11!
Dafna11 [192]

Answer:

The factorial of 11! is exactly 39916800

The number of trailing 0s in 11! is 2

The number of digits in 11 factorial is 8.

The factorial of 11 is calculated as below:

11! = 11 • 10 • 9 • 8 • 7 ... 3 • 2 • 1

Step-by-step explanation:

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3 years ago
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moinca spent 4/7 hours listening beethtoven and brahms. she spent 2/5 hours listening to beethtoven. how many hours were spent l
Makovka662 [10]
He spent 2\2 hours listening to brahms
8 0
3 years ago
use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos^4
Firdavs [7]

The expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8.</u>

The power-reducing formula, for cosine, is,

cos² θ = (1/2)[1 + cos 2θ].

In the question, we are asked to use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos⁴ θ.

We can do it as follows:

cos⁴ θ

= (cos² θ)²

= {(1/2)[1 + cos 2θ]}²

= (1/4)[1 + cos 2θ]²

= (1/4)(1 + 2cos 2θ + cos² 2θ] {Using (a + b)² = a² + 2ab + b²}

= 1/4 + (1/2)cos 2θ + (1/4)(cos ² 2θ)

= 1/4 + (1/2)cos 2θ + (1/4)(1/2)[1 + cos 4θ]

= 1/4 + cos 2θ/4 + 1/8 + cos 4θ/8

= 3/8 + cos 2θ/4 + cos 4θ/8

= [ 3 + 2cos 2θ + cos 4θ]/8.

Thus, the expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8</u>.

Learn more about reducing trigonometric powers at

brainly.com/question/15202536

#SPJ4

5 0
2 years ago
If a polynomial function f(x) has roots -9 and 7-i, what must be a factor of f(x)
Likurg_2 [28]

Hello from MrBillDoesMath!

Answer:

x + 9 and (x + ( i - 7)) are factors

Discussion:

If f(x) has roots -9 and 7-i then

f(x) = g(x)(x - (-9))  (x - (7-i))            ( g(x) is a polynomial of degree less than f(x))

That is, x + 9 and (x + ( i - 7)) are factors of f(x)

BTW: if the coefficients of f(x) are real (not stated in the Question) then the conjugate of 7-i, i.e. 7 + i, is  also be a root.

Thank you,

MrB

3 0
3 years ago
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