2 years ago

Solve. Express your answer as a simplified mixed number

Mathematics

2 answers:

Semmy [17]2 years ago

7 0

Stick change flip
5/6 x 10/3 = 50/18 2 14/18 simplify 2 7/9

Zinaida [17]2 years ago

7 0

2.7777 awnser pls mark brainliest

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mart [117]

Answer:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

tep-by-step explanation:

In order to find the integral:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx$

we can do the following substitution:

Let's call

$u=(x^3-x^2+x)$

Then

$du = (3x^2-2x+1) dx$

which allows us to do convert the original integral into a much simpler one of easy solution:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C$

Therefore, our integral written in terms of "x" would be:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

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3 years ago

Help me fjfjsncjdhdhfh

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Step-by-step explanation:

$=> 2 {x}^{2} + \frac{7}{2}x + \frac{3}{4} = 0$

$=> \frac{8 {x}^{2} + 14x + 3}{4} = 0$

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option C

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