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3 years ago

I don't understand how to do this. please help.

Mathematics

2 answers:

Darina [25.2K]3 years ago

6 0

Answer:

use the formula to find area, then multiply by the leingth, so 18 in your case. Also, the formula for area is A=(pi)r squared

Step-by-step explanation:

hope this helps

ira [324]3 years ago

5 0

Answer:

B. 3,052.08

Step-by-step explanation:

Radius:

r=d/2

r=18/2

r=9

Volume of Sphere:

V=(4/3)π $r^{3}$

V=(4/3)(3.14) $9^{3}$

V=(4/3)(3.14)729

V=(4/3)2289.06

V=3052.08

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Help please its too hard

Varvara68 [4.7K]

Answer:

#6 = 1; #7 = A (5 gallons)

Step-by-step explanation:

#6 it is 1 because you are suppose to divide 10% of 50 which gave yuu $5 and then divide 5 by 20% which is 1

6 0

3 years ago

Help....................................DDDDDDDDDDDDDDDDDDDDDDDDDDD

m_a_m_a [10]

Answer:

Step-by-step explanation:

a). Since, ΔABC ~ ΔWYZ

Their corresponding sides will be proportional.

$\frac{AB}{WY}=\frac{BC}{YZ}= \frac{AC}{WZ}$

$\frac{194}{WY}=\frac{BC}{1}= \frac{130}{WZ}$ --------(1)

By applying Pythagoras theorem in ΔABC,

AB² = AC² + BC²

BC² = AB² - AC²

BC² = (194)² - (130)²

BC² = 20736

BC = 144

From equation (1)

$\frac{194}{WY}=\frac{144}{1}= \frac{130}{WZ}$

$\frac{194}{WY}=\frac{144}{1}$

WY = $\frac{194}{144}$

WY = $\frac{97}{72}$ = 1.35

$\frac{144}{1}= \frac{130}{WZ}$

WZ = $\frac{130}{144}$

WZ = $\frac{65}{72}$ = 0.90

b). tan(A) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

= $\frac{144}{130}$

= $\frac{72}{65}$

Since, ΔABC ~ ΔWYZ,

∠A ≅ ∠W

Therefore, tangent of angle A and angle W will measure $\frac{72}{65}$ .

8 0

3 years ago

Which equation(s) have x = –3 as the solution? log3(2x + 15) = 2 log5(8x + 9) = 2 log4(–20x + 4) = 3 logx81 = 4

baherus [9]

Answer:

log_3(2x+15)=2 and log_4(-20x+4)=3

Step-by-step explanation:

Plug it in and see!

$log_3(2x+15)=2\\log_3(2(-3)+15)=2\\log_3(-6+15)=2\\log_3(9)=2\\\text{ This is a true equation because } 3^2=9\\\\\\log_5(8(-3)+9)=2\\log_5(-24+9)=2\\log_5(-15)=2\\\\\text{ Not true because you cannot do log of a negative number }\\\\log_4(-20(-3)+4)=3\\log_4(64)=3\\\text{ this is true because } 4^3=64\\\\\\log_x (81)=4\\log_{-3}(81)=4\\\text{ the base cannot be negative }\\\\\\\\\text{ There is only two options here} \\\\log_3(2x+15)=2 \text{ and } log_4(-20x+4)=3$