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egoroff_w [7]
3 years ago
11

Write the polynomial in standard form: x^2+4-3x

Mathematics
1 answer:
Sonbull [250]3 years ago
6 0

Answer:

x^2-3x+4

Step-by-step explanation:

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What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
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Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

x^{2} + y^{2}+8x-6y+21=0

The general equation of the circle is:

x^{2} + y^{2}+2gx+2fy+c=0

Comparing the given equation with the general equation we can say:

g = 4

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The formula for radius of the circle is:

radius=\sqrt{g^{2} +f^{2} -c }

Using these values of the given circle, we get:

radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2

Therefore, the length of radius of the given circle is 2.

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