It is NOT possible to determine the missing value from the given data.
<h3>Mean and Median</h3>
Mean is the average of a number of data while the median is the number at the middle of the given data.
- For a given data with a missing value, we can only find the missing value by calculating the mean of the data and equating the given mean.
Hence from the given data, it is NOT possible to determine the missing value from the given data.
Learn more on median and mean here; brainly.com/question/14805451
Let's assign John and Alex's points a variable.
John's Points: 2x-1
Alex Points: x
Now, let's set up an equation.
x+2x-1=23
Simplify.
3x-1=23
3x=23+1=24
3x=24
Now, to find x, or Alex's score, we divide.
24/3=8
Alex's Points= 8
Johns Points= (8*2)-1=15
There is your answer. If I helped than please vote brainliest!
Answer:
-4.67
Step-by-step explanation:
first find f^-1(x)
let f(x)=y
y=3x+2
3x=y-2
x=y-2/3
Therefore f^-1(x)=x-2/3
Now f^-1(-12)=-12-2/3
=-14/3
=-4.67
Answer:
C. Determine how many feet −55 feet is below zero feet.
D. Determine how far −55 is from zero on the number line
Step-by-step explanation:
Determine how many feet −55 feet is below zero feet.
This will give us the answer of 55feet , and the absolute value of -55 is 55.
0--55= 0+55 = 55
Determine how far −55 is from zero on the number line
This will also give me us 55 feet because the distance from 0 to -55 is 55
I.e. 0--55= 0+55 = 55
Answer:
0.0791
Step-by-step explanation:
student forgets iClicker device with probability 1/4 each time she attends a class.
She sets out with her iClicker device to attend 5 different classes
A - forget device
A' - do not forget device
P(A) = 1/4
P(A') = 3/4
If she arrives home without her iClicker device (after attending 5 classes), what is the probability (to 3 SIGNIFICANT figures) that she left it in the 5th class?
So, she will not forget in 1st class AND not forget in 2nd class AND not forget in 3rd class AND not forget in 4th class AND will forget in 5th class, so:
1st 2nd 3rd 4th 5th
3/4 3/4 3/4 3/4 1/4 = 0.0791