All categories

3 years ago

Mean of four numbers a ,b, c, and d is 8 and mean of seven

Mathematics

1 answer:

Nana76 [90]3 years ago

4 0

Answer:

17 1/3 or 17.33

Step-by-step explanation:

Mean of four numbers a, b, c, and d is 8:

(a + b + c + d)/4 = 8
⇒ a + b + c + d = 32

Mean of seven numbers x, y, z, a, b, c and d is 12:

(x + y + z + a + b + c + d)/7 = 12

Substitute the sum of 4 numbers:

x + y + z + 32 = 7*12
x + y + z = 84 - 32
x + y + z = 52

Mean of x, y and z is:

52/3 = 17 1/3 or 17.33

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Answer:

Step-by-step explanation:

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4 years ago

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Answer:

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3 years ago

From 12,000 graphing calculators produced by a manufacturer, an inspector selects a random sample of 550 calculators and finds

maria [59]

Answer:

131

Step-by-step explanation:

Using proportion,

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Then out of 12000 calculators = ? are defective

$\frac{12000 calculators}{550calculators} * 6$

= 21.8 * 6

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3 0

3 years ago

Find the value of x. 14 and 15

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Answer:

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Step-by-step explanation:

8 0

3 years ago

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0

3 years ago