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tiny-mole [99]
3 years ago
9

Was it evaluated correctly?explain your reasoning.​

Mathematics
1 answer:
NikAS [45]3 years ago
4 0

Answer:

It's not evaluated correctly

Step-by-step explanation:

in the problem 6 × 5 + 30 ÷ 30 we first need to multiply 6 and 5 then divide the 30 by 10 and finally add them up

6×5 = 30

30 ÷ 10 = 3

30 + 3 = 33

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What does (r−c)(3) mean about George's new store?
ANTONII [103]

subtract r from c to get 8x+10

 replace x with 3

8(3) +10 = 34 which in hundreds is 3400 dollars

the answer is C

3 0
3 years ago
I need help ASAP please
Brilliant_brown [7]

Answer:

28 cm

Step-by-step explanation:

The formula for the area of a triangle is 1/2bh

Here we have 1/2 (14)(4)

That comes to 28 cm

5 0
3 years ago
I need help with this one
Viefleur [7K]

that's-- on  edmentum isn't it?

first pair is -3

second pair is -2

third pair is 0'

and the last one is 5

that what i think it is .....????

7 0
3 years ago
Read 2 more answers
2. The angle of elevation of the top of a vertical
frozen [14]

Answer: 15.44 m

Step-by-step explanation:

We can think this as two triangle rectangles.

In both cases, the adjacent cathetus is 120m.

When the angle is 32°, the opposite cathetus will be the height of the cliff.

When the angle is 37°, the opposite cathetus will be the heigth of the cliff plus the height of the flagpole.

Then we need to compute both of them and calculate the difference.

We can use the trigonometric relation:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

in this case we have:

Tan(32°) = (height of the cliff)/(120m)

Tan(32°)*120m = height of the cliff = 74.98m

Now we can use the other angle to compute:

Tan(37°) = (heigth of the cliff + heigth of the flagpole)/120m

Tan(37°)*120m = heigth of the cliff + heigth of the flagpole = 90.42m

Then the height of the flagpole will be:

H = 90.42m - 74.98m = 15.44 m

6 0
3 years ago
I need help with number 4
tatuchka [14]
I u have the app better on your phone then go to shivani.kinare and like all the tips and comment and I will answer any question u want. I can also tutor u for free.
5 0
3 years ago
Read 2 more answers
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