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Angelina_Jolie [31]
3 years ago
9

The four points (−2, 5), (−2, −1), (5, −1), and (3, 5) are the vertices of a polygon. What is the area, in square units, of this

polygon?

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
8 0

Answer:

I say 33^2 or 36^2

Hope this helps :>

MariettaO [177]3 years ago
8 0

Answer:

c is the answer

Step-by-step explanation:

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You can get the max points i can give for this :)
andriy [413]

Answer:

{a}^{2}  +  {b}^{2}  =  {c}^{2} \\  {a}^{2}   +  {9}^{2}  =  {17}^{2}  \\  {a}^{2} =  289 - 81 \\  {a}^{2}  = 208 \\ a = 14.42cm

3 0
3 years ago
Solve 3(x-4)=-5 for x. Justify each step
igor_vitrenko [27]
3x - 12 = -5 plus 12
3x-12 +12 = -5+12
3x = 7 devision by 3
3x/3 = 7/3
x= 2,3333333333 =~ 2,3
4 0
3 years ago
Graph the image of this figure after a dilation with a scale factor of 2 centered at (2, 2) .
Fofino [41]

Answer:

The points of the dilated figure would be at (-2, 10), (2, 6), and (-8, 4); an image of the figure is attached.

Step-by-step explanation:

First we translate the center of dilation and figure so the origin becomes the center of dilation.

Since the point (2, 2) is our center of dilation, we must translate it left 2 and down 2 to make the origin the center; this means we map every point

(x, y)→(x-2, y-2)

The scale factor of 2 means that each point will be multiplied by 2; this gives us the rule

(x, y)→(2x-4, 2y-4)

Lastly we will translate the figure right 2 and up 2 to move it back to its original position; this gives us the rule

(x,y)→(2x-4+2, 2y-4+2) = (2x-2, 2y-2)

The first point in the original figure, at the top, is (0, 6).  Applying the transformation gives us

(0, 6)→(2*0-2, 2*6-2) = (0-2, 12-2) = (-2, 10)

The point on the right of the pre-image is (2, 4).  Applying the transformation rule gives us

(2, 4)→(2*2-2, 2*4-2) = (4-2, 8-2) = (2, 6)

The point on the left of the pre-image is at (-3, 3).  Applying the transformation rule, we have

(-3, 3)→(-3*2-2, 3*2-2) = (-6-2, 6-2) = (-8, 4)

7 0
3 years ago
Read 2 more answers
Write a pair of numbers such that the value of the 7 in the first number is 1000 times the value of the 7 in the second number,
telo118 [61]

<u>Answer-</u>

As infinitely many such possible number pairs can be formed, one of the instances of such pair would be (37000 and 307).

<u>Solution-</u>

Suppose the former one is aaaaa and the later one is bbbbb.

The value of 7 in the former is 1000 times greater than in the later, so let's make it 7000 and 7.

Then the numbers will be in the following form,

a7aaa and bbbb7

Again, the value of 3 in the former is 100 times greater than in the later.

Then the numbers will be in the following form,

37aaa and bb3bb7

Substituting all the a's and b's by 0,

we get, 37000 and 307 is a possible set. Replacing 0 with any number from 1-9, will yield another number pair which will satisfy the conditions.


6 0
3 years ago
Read 2 more answers
Please help me with this question​
aivan3 [116]

Step-by-step explanation:

the answer is

1) £30

2) £ 270

5 0
3 years ago
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