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BabaBlast [244]
3 years ago
12

Two endpoints of the diagonal of a parallelogram are k(0,3) and l(4,1). what is the length of the diagonal

Mathematics
1 answer:
posledela3 years ago
7 0
Distance = sqrt (x2 - x1)^2 + (y2 - y1)^2
(0,3).....x1 = 0 and y1 = 3
(4,1)....x2 = 4 and y2 = 1
now we sub and solve
d = sqrt (4 - 0)^2 + 1 - 3)^2
d = sqrt (4^2) + (-2^2)
d = sqrt (16 + 4)
d = sqrt 20
d = 4.472 <==
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tresset_1 [31]

Answer:

B. (x + 3) (x + 27)

Step-by-step explanation:

<em><u>To factor the expression, you must split the middle term (18x) into two terms that can be added to get 18, and multiplied to get 81:</u></em>

<em><u /></em>x^2 + 18x + 81

x^2 +3x + 27x + 81

<em><u>Group:</u></em>

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Which expressions are equivalent to ln x 2 ln 5 ln 1? Check all that apply. 2 ln 5x ln (x 26) ln 25x ln 1 ln 25x.
Marysya12 [62]

Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.The expressions which are equivalent to the given expression are,

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Given information-

The expression given in the problem is,

\ln x+2 \ln 5 +\ln1

<h3>Equivalent expression-</h3>

Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.

For given expression,

\ln x+2 \ln 5 +\ln1

As the above function is the function of <em>x. </em>Thus it can be written as,

f(x)=\ln x+2 \ln 5 +\ln1

<h3>Logarithm power rule</h3>

Logarithm power rule states that the exponent of the logarithm function can transfers to front of the logarithm and vice versa. Thus,

f(x)=\ln x+ \ln 5^2 +\ln1\\&#10;f(x)=\ln x+ \ln 25 +\ln1

Now the value of \ln 1 is equal to the zero. Thus,

f(x)=0+\ln 25 +\ln1\\&#10;f(x)=0+\ln 25 +\ln1\\&#10;f(x)=\ln 25 +\ln1\\&#10;f(x)=\ln 25 +0\\&#10;f(x)=\ln 25

Hence the expressions which are equivalent to the given expression are,

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Learn more about the equivalent expression here;

brainly.com/question/10628562

5 0
2 years ago
Read 2 more answers
Simplify
melomori [17]

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Step-by-step explanation:

For this exercise it is important to remember the following:

i=\sqrt{-1} \\\\i^2=-1

Given the following expression:

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You can notice that the radicand (the number inside the square root) is negative. Therefore, in order to simplify the expression, you need to follow these steps:

1. Replace \sqrt{-1} with i and simplify:

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2. Descompose 12 into its prime factors:

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3. Substitute into the expression:

=2\sqrt{2^2*3}

4. Since \sqrt[n]{a^n}=a, you can simplify it:

=(2)(2)\sqrt{3}=4\sqrt{3}

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