For x-intercepts "b" and "c", a quadratic can be written as
y = a(x -b)(x -c)
You know the x-intercepts, so you can write the equation as
y = a(x +2)(x -3) . . . . . . eliminates the first two answer choices
Substituting (x, y) = (-1, 2), you have
2 = a(-1+2)(-1-3) = -4a
Then dividing by -4 gives
-2/4 = a = -1/2 . . . . . corresponds to the third answer choice
The appropriate selection is
y = -1/2 (x + 2)(x - 3)
Answer:
x = 22, y = -4
Step-by-step explanation:
x + 6y = -2 --- Equation 1
-x = 3y - 10 --- Equation 2
Equation 2 ×(-1): x = -3y + 10 --- Equation 3
Substitute x = -3y + 10 into Equation 1:
x + 6y = -2
-3y + 10 + 6y = -2
3y + 10 = -2
3y = -2-10
= -12
y = -12 ÷ 3
y = -4
Substitute y = -4 into Equation 3:
x = -3y + 10
x = -3(-4) + 10
= 12 + 10
x = 22
Dimension= width
So,
344/8= 43
The "width" or dimension, is 43.
I hope this helps!
~cupcake
Angle A = 130° and Angle B = 110°
Solution:
Given ABCD is a trapezoid with ∠C = 70° and ∠D = 50°
If ABCD is a trapezoid, then AB is parallel to CD.
AD is a transversal to AB and CD and
BC is a tranversal to AB ad CD.
Sum of the interior angles on the same side are supplementary.
∠A + ∠D = 180°
⇒ ∠A + 50° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠A = 180° – 50°
⇒ ∠A = 130°
Similary, ∠B + ∠C = 180°
⇒ ∠B + 70° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠B = 180° – 70°
⇒ ∠B = 110°
Hence, angle A = 130° and angle B = 110°.
Answer:
-3y
Step-by-step explanation:
-15(y2)4 ÷5y3y4
Rewrite the division as a fraction
<u>-15(y2)4</u>
5y3y4
Multiply y3 by y4 by adding the exponents
<u>-5(y2)4</u>
5y7
Cancel the common factor of -15 and 5
<u>-3(y2)4</u>
y7
Multiply the exponents in (y2)4
<u>-3y8</u>
y7
Cancel the common factor of y8 and y7
Factor y7 out of -3y8
<u>y7(-3y)</u>
y7
Multiply by 1
<u>y7(-3y)</u>
y7 × 1
Cancel the common factor which is y7 and y7
Rewrite the expression
<u>-3y</u>
1
Divide -3y by 1
-3y
