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nevsk [136]
3 years ago
9

Can someone help me, lol?

Mathematics
2 answers:
Setler [38]3 years ago
8 0

Answer:

The modes are 9 and 11

Step-by-step explanation:

sattari [20]3 years ago
7 0

The mode is the value that appears most frequently in a data set. A set of data may have one mode, more than one mode, or no mode at all. ... The mode can be the same value as the mean and/or median, but this is usually not the case.

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What is the tangent ratio for ∠A?<br><br><br>6/8<br><br><br>8/6<br><br><br>10/8<br><br><br>8/10
makkiz [27]

Tangent is Opposite over adjacent.


The opposite side of Angle A is 6 and the adjacent side is 8.


The tangent ratio would be 6/8



8 0
3 years ago
I need help please <br> i dont get it
eimsori [14]
The answer would be 329.49

To withdraw means to take money out, so you would subtract.

A deposit is to add money so you would add money
4 0
3 years ago
Last One Please Help
tigry1 [53]

Answer: A. 3/5

Step-by-step explanation:

Count all the add numbers in 1-10 then add the 4 and you get

6/10

Simply and you get 3/5

7 0
3 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
Y = –x + 4<br> x + 2y = –8
valkas [14]
X=16
y= -12


X+2( -x+4)=-8
X-2x+8=-8
-1x=-16
X=16

Y=-16+4
Y=-12
8 0
4 years ago
Read 2 more answers
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