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alisha [4.7K]
4 years ago
7

Priya is walking down a long hallway.She walks halfway and stops.Then she walks half of the remaining distance and stops again.s

he continúes to stop every time she goes half of the remaining distance. A. What fraction length of the halfway will Priya have covered after she starts and stops 2 times?
Mathematics
1 answer:
slega [8]4 years ago
8 0

1/1

Step-by-step explanation:

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The real numbers $x$ and $y$ are such that \begin{align*} x + y &= 4, \\ x^2 + y^2 &= 22, \\ x^4 &= y^4 - 176 \sqrt{
tamaranim1 [39]

You get everything you need from factoring the last expression:

x^4-y^4=-176\sqrt7

The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with

x^4-y^4=(x^2-y^2)(x^2+y^2)=(x-y)(x+y)(x^2+y^2)

Plug in everything you know and solve for x-y:

-176\sqrt7=(x-y)\cdot4\cdot22\implies x-y=\boxed{-2\sqrt7}

4 0
3 years ago
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Need help on #7 help if u know how to solve thanks!
mash [69]
7a) 302.5
7b) 302500
Hope this helps! :)
8 0
3 years ago
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Solve the equation: 13W - 2(4W + 1) = W - 58 *
Sergio [31]

Answer:

W = - 14

Step-by-step explanation:

13W - 2(4W + 1) = W - 58

13W - 8W - 2 = W - 58

13W - 8W - W = 2 - 58

4W = - 56

W = - 56 : 4

W = - 14

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3 years ago
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1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

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3 years ago
32 ÷ 4 x (16 x 1/2) -2
Anika [276]

32 ÷ 4 x (16 x 1/2) -2

= 32 ÷ 4 × 8 -2

= 8 × 8 - 2 = 64-2

= 62

3 0
2 years ago
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