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wolverine [178]
2 years ago
8

40 ounces to pounds as a mixed number in simplest form with equation

Mathematics
1 answer:
balandron [24]2 years ago
7 0
There is 16 ounces in a pound, so you would have to divide 40 by 16 getting 2 1/2.
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The expression 4g gives the number
jeka57 [31]

Answer: 16 quarts.

Step-by-step explanation:

1 quart = 1/4 gallon.

4 quarts = 1 gallon.

If you have 4 gallons, then you need to multiply 4 by 4, because every gallon is equal to 4 quarts.

4 x 4 = 16.

Therfore, there are 16 quarts in 4 gallons.

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3 years ago
Given that a trapezoid has the following dimensions, find the area. Area = ________ units2
rjkz [21]
The formula for the area of a trapezoid is A = a+b/2 * h. So just plug in the dimensions.
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3 years ago
A gallon of paint will cover approximately 350 square feet and artist wants to paint all the outside surfaces of a cube measurin
Gelneren [198K]
Assuming that the artist wants to paint 6 sides of the cube, the formula to count the surface area of the cube would be: 6* edge length^2. If the edge length is 10 feet, then the area would be:
area= 6*edge length^2
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If one gallon of paint can be used for 350 feet^2, the amount of paint needed would be: 600feet^2/ (350ft^2/ gallon)= 1.71 gallon
8 0
3 years ago
WILL mark brainliest!
Angelina_Jolie [31]

Answer:

  110.5348 minutes

Step-by-step explanation:

The difference from room temperature changes from 103 to 59 in 46 minutes, so that difference can be modeled by the exponential equation ...

  Δt = 103×(59/103)^(t/46)

We want to find t for the temperature difference Δt = 91 -64 = 27.

  27 = 103×(59/103)^(t/46)

  27/103 = (59/103)^(t/46) . . . . . divide by 103

Taking logs gives the linear equation ...

  log(27/103) = (t/46)log(59/103)

Multiplying by the inverse of the coefficient of t, we get ...

  t = 46·log(27/103)/log(59/103) ≈ 46·(-0.58147346)/(-0.24198521)

  ≈ 110.5347

It will take about 110.5347 minutes for the turkey to cool to 91 °F internally.

_____

<em>Comment on 4 decimal places</em>

An answer correct to 4 decimal places (7 significant digits) is a pretty good indication that the problem was worked correctly. However, that level of precision in the timing makes little sense in this context. Most thermometers will take at least a few seconds to register the temperature to within a tenth of a degree or so. This problem is asking for an answer that is within 6 milliseconds and 30 micro-degrees. Neither of these is anywhere near realistic for a kitchen meat thermometer.

More realistic would be an answer to 4 <em>significant figures</em>, a tenth of a minute and a few hundredths of a degree.

(The rate of change at the time of interest is about -0.33 degrees per minute.)

6 0
3 years ago
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