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stich3 [128]
3 years ago
13

Find the length of leg " a" if leg "b" = 12 and the hypotenuse "c" is 13

Mathematics
1 answer:
quester [9]3 years ago
3 0
A^2 + b^2 = c^2

a^2 + (12)^2 = (13)^2

a^2 + 144 = 169

a^2 = 169 - 144

a^2 = 25

Sqrt (a^2) = Sqrt(25)

a = 5

Please mark brainliest if this helps
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Find all polar coordinates of point P = (6,31°). Plz explain the steps :)
mrs_skeptik [129]
<span>P = (6,31°) is already a polar coordinate.

In the notation (r, </span>α) if you make r negative, it points in the opposite direction. If you add 180° to α you compensate for that.

Therefore (6,31°) = (-6,31°+180°) = (-6, 211°)

However, it is more usual to keep r positive.
5 0
3 years ago
A ship travels due north for 100 miles from point C to point A. From point A the ship travels to point B at 60° east of north. F
Karo-lina-s [1.5K]

Answer:

AandB=80miles

Total=240miles

Step-by-step explanation:

Draw the figure first indicating the figures then find the distance each degrees then find the total

4 0
3 years ago
Evaluate log base 16 0.25​
AveGali [126]

Answer:

Step-by-step explanation:

Rewrite log16(0.25)

using the change of base formula.

Exact Form:

log(0.25)log(16)

Decimal Form:

−0.5

5 0
3 years ago
15% of 72 is ______​
BigorU [14]

Answer: convert 15% to a decimal. 0.15 times 75 is 11.25

Converting Percentages to Decimals

Easiest—divide by 100: The simplest way to convert a percentage to a decimal is to divide the number (in percentage format) by 100.

Move the decimal: Another way to convert a quoted percentage to decimal format is to move the decimal two places to the left

6 0
3 years ago
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
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