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Paul [167]
3 years ago
10

On new years Eve,The temperature fell by 24 degrees in a span of 6 hours by how many degrees did the temperature fall every hour

?
Mathematics
2 answers:
RoseWind [281]3 years ago
5 0

Answer:

4 degrees

Step-by-step explanation:

24 degrees :6 hours

divide by 6 for the unit rate.

4 degrees : 1 hour

OlgaM077 [116]3 years ago
3 0

Answer:

4 degrees

Step-by-step explanation:

24 divided by 6 is 4

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if the heart of an elephant , at rest beat an average of 1680 beats in 60 min . What is the rate in beats per minute
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3 years ago
FInd the circumference of a circle with a diameter of 6 yd. Use the value 3.14 for x and do not round your answers
Varvara68 [4.7K]

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Step-by-step explanation:

5 0
2 years ago
A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and
Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.​

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

Hypotenuse^2=Base^2+Perpendicular^2

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

(9.85)^2=x^2+(x+5)^2

97.0225=x^2+x^2+10x+25

0=2x^2+10x+25-97.0225

0=2x^2+10x-72.0225

Here, a=2, b=10,c=-72.0225. Using the quadratic formula, we get

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}

x=\dfrac{-10\pm \sqrt{676.18}}{4}

Approximating the value, we get

x=\dfrac{-10\pm 26}{4}

x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}

x=\dfrac{16}{4},\dfrac{-36}{4}

x=4,-9

Distance cannot be negative so x\neq -9.

Now we have x=4

x+5=4+5

x+5=9

Therefore, the base is 4 m and the height is 9 m.

5 0
3 years ago
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