975 x 1.01 = 984.75
984.75 x 1.09 = 1073.38
Answer:
a² + b² = 68
a3 + b3 = 520
Step-by-step explanation:
Given :
a + b = 10 (1)
ab = 16 (2)
A. Find a² + b²
(a + b)² = a² + 2ab + b² (3)
Substitutite the values of (1) and (2) into (3)
(10)² = a² + 2(16) + b²
100 = a² + 32 + b²
Subtract 32 from both sides
100 - 32 = a² + b²
a² + b² = 68
B. a^3 + b^3
(a + b)^3 = a^3 + b^3 + 3ab(a + b)
(10)^3 = a^3 + b^3 + 3*16(10)
1000 = a^3 + b^3 + 480
a^3 + b^3 = 1000 - 480
a3 + b3 = 520
Answer:
x = 500 yd
y = 250 yd
A(max) = 125000 yd²
Step-by-step explanation:
Let´s call x the side parallel to the stream ( only one side to be fenced )
y the other side of the rectangular area
Then the perimeter of the rectangle is p = 2*x + 2* y ( but only 1 x will be fenced)
p = x + 2*y
1000 = x + 2 * y ⇒ y = (1000 - x )/ 2
And A(r) = x * y
Are as fuction of x
A(x) = x * ( 1000 - x ) / 2
A(x) = 1000*x / 2 - x² / 2
A´(x) = 500 - 2*x/2
A´(x) = 0 500 - x = 0
x = 500 yd
To find out if this value will bring function A to a maximum value we get the second derivative
C´´(x) = -1 C´´(x) < 0 then efectevly we got a maximum at x = 500
The side y = ( 1000 - x ) / 2
y = 500/ 2
y = 250 yd
A(max) = 250 * 500
A(max) = 125000 yd²
The Original Price is $40
Explanation:
50 1 20
—- = — Which means ——
100 2 40
A. x=the cost of one lunch. 60.25=5x+3(x-5.25)
b. 60.25=5x+3x-15.75 60.25+15.75=8x-15.75+15.75
76=8x 76/8=8x/8 9.50=x
A lunch is $9.50. If you are not sure, check my answers. Hope this helped.
