Answer:
the answer is 9 :)
Step-by-step explanation:
There would be 35 rulers.
In order to solve this, use cross multiplication.
6/10 = 21/x -----> cross multiply
10*21 = 6*x
210 = 6x
35 = x
Yeah the first one (A) seems like the best to me :)
1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)
When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)
2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;
A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
7/8 in decimal form is 0.875 because you are dividing 7 by 8