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alexira [117]
3 years ago
13

If BE−→− bisects ∠ABD and m∠EBD = 32°, find m∠ABD.

Mathematics
2 answers:
Eva8 [605]3 years ago
8 0

Check the picture below.

zvonat [6]3 years ago
4 0

Answer:

m\angle ABD=64^{\circ}

Step-by-step explanation:

We have been given that segment BE bisects \angle ABD and m\angle EBD=32^{\circ}. We are asked to find the measure of angle ABD.

Since BE is angle bisector of angle ABD, so measure of angle EBD will be equal to measure of angle ABE.

The measure of angle ABD will be 2 times the measure of angle EBD.

m\angle ABD=2\times m\angle EBD

m\angle ABD=2\times 32^{\circ}

m\angle ABD=64^{\circ}

Therefore, the measure of angle ABD is 64 degrees.

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8 0
3 years ago
If m< BCD = 54, find m< BAC
dmitriy555 [2]

m∠BAC = 27°

Solution:

ABCD is a quadrilateral.

AB and CD are parallel lines.

Given m∠BCD = 54°

AC bisect ∠BCD.

m∠DCA + m∠CAB = m∠BCD

m∠DCA + m∠DCA = 54°   (since ∠ACB = ∠DCA)

2 m∠DCA  = 54°

Divide by 2 on both sides, we get

m∠DCA  = 27°

AB and CD are parallel lines and AC is the transversal.

<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>

m∠BAC = m∠DCA

m∠BAC = 27°

Hence m∠BAC = 27°.

7 0
3 years ago
Which of the following is best used to measure the weight of a 18-wheeler truck
Katen [24]
the answer to this would be tons
6 0
3 years ago
Desde la parte más alta de un edificio a 25 m una persona lanza hacia la base un objeto de 150 g con una velocidad de 0.8 m por
ANTONII [103]

Answer:

E_{T} = 36.84 J        

Step-by-step explanation:

La energía mecánica total está dada por:

E_{T} = E_{c} + E_{p}

E_{T} = \frac{1}{2}mv^{2} + mgh

En donde:

m: es la masa = 150 g

v: es la velocidad = 0.8 m/s

h: es la altura = 25 m

g: es la gravedad = 9.81 m/s²

E_{T} = \frac{1}{2}mv^{2} + mgh = \frac{1}{2}0.15 kg*(0.8 m/s)^{2} + 0.15 kg*9.81 m/s^{2}*25 m = 36.84 J

Por lo tanto, la energía mecánica total es 36.84 J.

Espero que te sea de utilidad!      

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3 years ago
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notka56 [123]
X/8-1/2=6
X/8=6+1/2=13/2
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X=52
3 0
3 years ago
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