Solve for the missing side ?

Mathematics

1 answer:

guajiro [1.7K]3 years ago

7 0

Answer:

BC = x = 8.12

AB = 15.33

Step-by-step explanation:

The missing sides of the right triangle is AB and BC;

Step 1: solve for BC using the following formula;

$tan(\theta) = \frac{Opposite \ side}{Adjacent \ side} \\\\tan (32)= \frac{BC}{AC} \\\\tan(32) = \frac{x}{13} \\\\x = 13 \times tan(32) \\\\x = 8.12 \$

Step 2; solve for AB using a trig ratio or Pythagoras theorem;

$cos (\theta) = \frac{Adjacent \ side }{Hypotenuse \ side} \\\\cos (32) = \frac{AC}{AB} \\\\cos (32) = \frac{13}{AB} \\\\AB = \frac{13}{cos (32)} \\\\AB = 15.33$

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Step-by-step explanation:

$f(x) =\begin{cases} x & \quad x < 3\\x+3 & \quad x \geq 3\\\end{cases}$

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We need consider only the point at which the pieces meet (x = 3).

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