To get the number of members between 15 years and 30 years we proceed as follows:
z=(x-μ)/σ
where:
mean,μ=23
standard deviation, σ=4 years
thus
P(15<x<31)
when x=15
P(x<15)
z=(15-23)/4
z=-2
thus
P(x<15)=P(z<-2)=0.0228
when x=31
z=(31-23)/4
z=2
thus
P(x<31)=P(z<2)=0.9772
Hence:
P(15<x<31)=0.9544
hence the number of members between that age was:
0.9544×300
=286.32 people
~285 People
Answer: 285 people
4-6, because it is the largest
Answer: wow
I'd want nothing more than to swim in a pool of saliva.
Answer:
The area is 432cm squared.
Step-by-step explanation:
To find the area, first you split the figure into 2 rectangles.
The rectangle facing up would be 8cm by 30cm, and the rectangle pointing to the left would be 8cm by 24cm (because you subtract 8 by 32). Next, with those numbers, you can easily find the area. 8cm x 30cm equals to 240cm squared, and 8cm x 24cm equals to 192cm squared. Lastly, you add the both of the areas together, 240cm and 192cm, and you get 432cm squared.
The answer is: [C]: " ⁷/₆ " .
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Note:
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(5/3) - (1/2) = ? ;
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The LCD (lowest common denominator) of "2 and 3" is "6" ;
So we need to rewrite EACH fraction in the problem as a fraction with "6" in the denominator ;
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(5/3) = (?/6) ? ; (6÷3=2) ; (5/3) = (5*2)/(3*2) = 10/6 ;
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(1/2) = (?/6) ? ; (6÷2=3) ; (1/2) = (1*3)/(2*3) = 3/6 ;
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Rewrite the problem: " (5/3) - (1/2) " ; as:
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10/6 - 3/6 ;
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10/6 - 3/6 = (10 - 3) / 6 = (7/6) = 1 ⅙ .
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The answer is: " ⁷/₆ " ; or, write as: " 1 ⅙ " ; which corresponds to:
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Answer choice: [C]: " ⁷/₆ " .
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