Number 8 pleaaaaaaseeeeeeeeeeeeeee

Mathematics

2 answers:

ivanzaharov [21]3 years ago

8 0

A. 20
B. 1/5
!!!!!!!!!

n200080 [17]3 years ago

8 0

Answer:

its b [what is the ratio ] hope this helps

Step-by-step explanation:

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Josh is hiking Glacier National Park. He has now hiked a total of 17 km and is 2 km short of being half of the way done with thi

poizon [28]

Hello!

What we know so far is that Josh has hiked 17km. He is 2km short of being half way done with the hike.

To solve this, we must add 17 and 2 (to find the kilometers that he has hiked and the kilometers that he needs to hike to reach half way.)
17+2= 19

Now we know that 19km is exactly halfway in Josh's hike.
To find the total amount of km in Josh's hike, we must multiply 19 by two. (Half way times two = total amount)

19x2= 38

The total amount of kilometers in Josh's hike is 38km.

I hope this helps you!!

8 0

3 years ago

A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial,

Tresset [83]

Answer:

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

Step-by-step explanation:

Given - A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and it will choose the other foods on the next trial with equal probabilities of 25%.

To find - If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

Proof -

By the given information, we get the stohastic matrix

$H = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]$

As we know that,

The matrix is a Markov chain $x_{k+1} = Hx_{k}$

Let

The initial state vector be

$x_{0} = \left[\begin{array}{ccc}1\\0\\0\end{array}\right]$

we choose this initial vector because given that If the animal chooses food #1 on an initial trial.

Now,

$x_{1} = Hx_{0} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}1\\0\\0\end{array}\right] \\= \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]$

∴ we get

$x_{1} = \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]$

Now,

$x_{2} = Hx_{1} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right] \\= \left[\begin{array}{ccc}0.25+0.0625+0.0625\\0.125+0.125+0.0625\\0.125+0.0625+0.125\end{array}\right]\\= \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]$