(t-1)(t+1) = t^2-1 through the difference of squares rule
So,
(t-1)(t+1)(t^2+1)
(t^2-1)(t^2+1)
(x-1)(x+1) ... let x = t^2
x^2-1 .... another application of the difference of squares rule
(t^2)^2 - 1... plug in x = t^2
t^4 - 1
Apply the radical rule to separate terms:
Cubicroot(-27) and cubic root(n^27)
Cubicroot(-27) = -3
Now you have -3 cubicroot(n^27)
Using the exponent rule
N^27 can be rewritten as (n^9)^3
Now you have -3 cubicroot((n^9)^3)
The cubic root and the 3rd power cancel out to get the final answer of
-3n^9
Answer:
35, 37 , 39
Step-by-step explanation:
there is an interval of 2 between consecutive odd numbers
let the 3 consecutive odd numbers be n , n + 2 , n + 4 , then
n + n + 2 + n + 4 = 111
3n + 6 = 111 ( subtract 6 from both sides )
3n = 105 ( divide both sides by 3 )
n = 35
n + 2 = 35 + 2 = 37
n + 4 = 35 + 4 = 39
the 3 consecutive odd numbers are 35 , 37 , 39
Answer: c) tan x = 43/18
Step-by-step explanation:
Tan = Toa = Opposite/Adjacent
Answer:be careful
Dont let then overpower you
And be toxic and salty but not too much
Good luck
Step-by-step explanation: