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otez555 [7]
3 years ago
8

1.) Is the graph above a function? Why

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0
1.) Yes this graph is a function. Why? It passes the line test and there is only one value of x.
2.) More information is needed about maximum
3.) (-1,1) (1,1)
4.) I am not sure
5.) I am not sure
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If f(x)=-2x-3 what is f(r+2) ?
fiasKO [112]

Answer:

f(x) =  - 2x - 3

when x is r + 2 :

f(r + 2) =  - 2(r + 2) - 3 \\  =  - 2r - 4 - 3 \\  =  - 2r - 7 \\  \\ { \boxed{ \boxed{f(r + 2) =  - 2r - 7}}}

4 0
3 years ago
What is the weight of a 24.52kg Television dropped on pluto (acceleration of 0.59 m/s2
AVprozaik [17]

weight is a force

force=mass times acceleration

weight=24.52*0.59=14.4668N

5 0
3 years ago
Clayton is shopping for a new shower. He is comparing the water usage of cach as he is shopping .
Jlenok [28]
What else ? Is that it ?
7 0
2 years ago
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
Adam divides 32/8032. In which place should he write the first digit of the quotient?
kow [346]

Answer:

We have a quotient between a 2 digit number and a 4 digit number.

The usual rule for this type of problems is:

If the denominator has n more digits than the numerator, then the first digit will be in the nth position at the right of the decimal point.

If also, the denominator is larger than the numerator times 10^n, then the decimal will be moved another place to the right.

For example, if we divide 10 by 100 we have:

10/100

The denominator has one more digit than the numerator, then n = 1.

this means that the first digit of the quotient, will be on the first place at the left of the decimal point.

We can solve the quotient to get:

10/100 = 0.1

And, as we predicted, the first decimal is in the first place.

Now, with our quotient we have:

32/8032

n = 2.

and:

32*10^n = 3200

The denominator is larger than this, then we will move the first decimal to another place to the right.

Then we should expect to have the first decimal in the third place after the decimal point.

We can solve the quotient to get:

32/8032 = 0.0039

As we expected.

3 0
2 years ago
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