Where the variance is 0.32, the mean is 0.40, and there are provided sets of probabilities, the standard deviation will be 0.566.
<h3>What is standard deviation?</h3>
The average degree of variability in your dataset is represented by the standard deviation. It reveals the average deviation of each statistic from the mean. In general, values with a high standard deviation are spread out from the mean, whereas those with a low standard deviation are grouped together close to the mean.
Here,
mean=0.4
variance=(Xn-mean)².P(x)n
=(0-0.4)²*(0.64)+(1-0.4)²*(0.32)+(2-0.4)²*0.04
variance=0.32
Standard deviation=√(variance)
=√0.32
=0.566
The standard deviation will be 0.566 where variance in 0.32 and mean is 0.40 and given sets of probability.
To know more about standard deviation,
brainly.com/question/13905583
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In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.
In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.
In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...
9/17 = 18/34
15/34
6/17 = 12/34
9/34
Now we see that each number is the previous number minus 3/34, so we have a common difference of 3/34.
This would match the definition of an arithmetic sequence and NOT a geometric sequence.
Answer:16
Step-by-step explanation:Next day there will be (36+12) or 48 players.
For 36 players 12 pizzas are needed
For 1 player 12/36 pizzas are needed
For 48 players 12/36*48 or 16 pizzas are needed
Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:

a) 
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082

b) 
The area to the left of z=3.00 is 0.9987

c) The z-value of 1200 is 0
The area to the left of 0 is 0.5

The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e) 
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1
Answer:
i believe it's "(x+3)(x+3)(x+3)" but double check me on that.