Using the t-distribution, it is found that the 99% confidence interval for the difference is (0.058, 3.462).
We are given the <u>standard deviation for the samples</u>, hence, the t-distribution is used to solve this question.
The standard errors are given by:


For the distribution of differences, the <u>mean and the standard error</u> are given by:


The interval is given by:

The critical value for a <u>two-tailed 99% confidence interval</u> with 18 + 18 - 2 = <u>34 df</u> is t = 2.7284.
Then:


The 99% confidence interval for the difference is (0.058, 3.462).
For more on the t-distribution, you can check brainly.com/question/16162795
Answer:
Solve w + 2 = 7w - 16 to find the value of w
The answer:
((x-3)^14)/14 + (6*(x-3)^3)/13 + (3*(x-3)^12)/4 + C
I believe the answer is Chord AB