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dusya [7]
2 years ago
12

Helppppp pleazeee!!!

Mathematics
2 answers:
Dmitriy789 [7]2 years ago
6 0

Answer:

wooo

Step-by-step explanation:

Tomtit [17]2 years ago
3 0
I believe the answer is Chord AB
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Find the Volume of this Octagonal Pyramid.<br> "B" represents the Area of the octagon base.
Dominik [7]

Answer:

7.06 x 10^(-7) ft 3

Step-by-step explanation:

We have the formula to calculate the volume of an octagonal Pyraamid as following:

<em>+) Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>

As given, the base of the pyramid is an octagon with area equal to 15mm2

=> Area of the base = 15 mm2

The height of the pyramid is the length of the line segment which is perpendicular to the base - which is the red line.

=> Height = 4mm

So we have:

<em>Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>

<em>= 1/3 * 15 * 4 = 20 mm3</em>

<em />

As: 1 mm3 = 3.53 x 10^(-8) ft 3

=> 20 mm3 = 7.06x10^(-7) ft 3

So the volume of the pyramid is :  7.06 x 10^(-7) ft 3

6 0
3 years ago
In the figure below, XZ =DF and _X = D.
yuradex [85]

Answer:

Option (4)

Step-by-step explanation:

Given : XZ ≅ DF and ∠X ≅ ∠D

To prove : ΔXYZ ≅ ΔDEF

Statements                               Reasons

1). XZ ≅ DF                                 1). Given

2). ∠X ≅ ∠ D                              2). Given

3). XY ≅ DE                                3). Required information

4). ΔXYZ ≅ ΔDEF                      4). By SAS property of congruence

Therefore, Option (4) will be the answer.

4 0
3 years ago
Linda goes water-skiing one sunny afternoon. After skiing for 15 min, she signals to the driver of the boat to take her back to
trasher [3.6K]
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2


abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.


d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
4 0
3 years ago
Solve please. Just give the answer plz!
Studentka2010 [4]

Answer:

I think the answer is 6 hours. I'm not sure though

5 0
3 years ago
Read 2 more answers
If 5 friends buy a package of 38 balloons, how should they divide them?
Nastasia [14]
All you have to do is divide 38 divided by 5 which = 7 r 3

I hope this helps. 

Have a awesome day. :)
7 0
2 years ago
Read 2 more answers
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