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Irina-Kira [14]

3 years ago

15

Dan and David are marking exam papers. Each set takes Dan 35 minutes and David 1 hour. Express the times Dan and David take as a

ratio.
Give your answer in its simplest form.

1 answer:

blagie [28]3 years ago

8 0

Answer:

Step-by-step explanation:

1 hour =60 minutes

Ratio =35

60

= 7

12

Answer=7

12

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Cmon smart ppl lets get this bread

KiRa [710]

Answer:

It has a scalar factor of 2.5

Step-by-step explanation:

You can just look at the bottom, the first shape has a bottom of 4 square while the second image has a bottom of 10 squared. You can divide the two to get the scaling factor. 10/4 = 2.5

You can also see one of the side square

6 0

4 years ago

1)Make an area model(Table) or a tree diagram to model all the possible combinations in this situation. 2)What is the theoretica

Ann [662]

Answer:

Example:

A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.

a) Construct a probability tree of the problem.

b) Calculate the probability that Paul picks:

i) two black balls

ii) a black ball in his second draw

Solution:

tree diagram

a) Check that the probabilities in the last column add up to 1.

b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.

ii) There are two outcomes where the second ball can be black.

Either (B, B) or (W, B)

From the probability tree diagram, we get:

P(second ball black)

= P(B, B) or P(W, B)

= P(B, B) + P(W, B)

6 0

3 years ago

Does anyone know the answer?

motikmotik

Answer:

We conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

Step-by-step explanation:

From the given right-angled triangle,

Base = p+1

Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

$=\frac{1}{2}\left(p+1\right)\left(2p-6\right)$

Factor 2p-6: 2(p-3)

$=\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}$

Divide the number: 2/2 = 1

$=\left(p+1\right)\left(p-3\right)$

$\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

$=pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)$

$=pp-3p+1\cdot \:p-1\cdot \:3$

$=p^2-2p-3$

Therefore, we conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

3 0

3 years ago

If 2 - 2 is a factor of 2.? - bx - 10, what is the value of b?

aleksandr82 [10.1K]

Bajanhxhsjsjshsjsjshhshshshsheh

7 0

3 years ago

Three unit squares (1-by-1 squares) and two line segments connecting two pairs of vertices are shown.

nasty-shy [4]

Answer:

Step-by-step explanation:

I don't know if, just because I'm a high school math teacher, I way over-think things, but the method I used to come to the answer here is crazy and convoluted...but it works. Follow me here while I explain it.

I put that drawing you have there in a coordinate plane and made a point D at the end of the segment that begins with A; made a point E at the end of the segment that begins with B. Putting that into a coordinate plane with E at the origin gives A coordinates of (0, 2); B (1, 2); D (2, 1). We need to find the coordinates of C to use later. That's the first job.

When you put this into a coordinate plane, it allows you to write the equations of the segments AD and BE.

AD: y = -1/2x + 2

BE: y = 2x

If you set these equal to each other, you can see where the lines intersect (the coordiantes of this point) by solving for x and y.

-1/2x + 2 = 2x and

2.5x = 2 so

x = .8

And if x = .8, we can sub that into either equation to find y:

y = 2(.8) so

y = 1.6

So the coordinates of C are (.8, 1.6).

Now we can find the lengths of each of these segments AC and BC. We already know that the length of segment AB is 1.

Find the lengths of each of these segments using the coordinates for each in the distance formula. The lengths are as follows:

AC = .8944

BC = .4472

This allows me to use the Law of Cosines to find the measure of angle A.

Angle A = 26.56°

Now I can use the area formula for a triangle that says

$A_{triangle}=\frac{1}{2}AB*ACsinA$ and

$A=\frac{1}{2}(1)(.8944)sin26.56$ so

A = .1999 units squared

8 0

3 years ago