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4 years ago

What's the answer to this inequality?

Mathematics

1 answer:

iris [78.8K]4 years ago

3 0

This is like an equation but with out the equal sign, you have to isolate the variable so on the side with the variable, e and 2 are dividing so we do reverse oporations. (if variable ia multiplying you divide is varisble is subtracting you add vise versa) We multiply by 2 on both sides so 3 times 2 is 6 and e < 6

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1 quart of milk is about 945 mm of milk uses information to compare quart and a liter

Katen [24]

Answer:

1 quart is .945 L

Step-by-step explanation:

There are 1000 millie litres in a litre because millie means thousandth; thus, 1 quart =.945 L

8 0

4 years ago

Which is the most accurate measurement for the line segment?

sdas [7]

Answer:

Step-by-step explanation:

So, a line segment is a piece or part of a line having two endpoints. Unlike a line, a line segment has a definite length. The length of a line segment can be measured either in metric units such as millimeters, centimeters, or customary units like feet or inches.

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3 years ago

What is the height of a triangle with a base of 6 yards and an area of 72 square yards?

ANEK [815]

Answer:

Step-by-step explanation:

the height of a triangle is A=(b·h)÷2

We know the area and base so replace: 72=(6×h)÷2

Solve:

72=(6×h)÷2

·2 ·2

144=6h

÷6 ÷6

h=24

24 yards

4 0

3 years ago

Como puedo resolver este ejercisio ( algebra 1 )

Gelneren [198K]

Numero 6; x less than or equal to 1
numero;7; 4x+3<-5
4x<-8
x= -2
Eso es fasil

3 0

4 years ago

The probabilities that a batch of 4 computers will contain 0, 1, 2, 3, and 4 defective computers are 0.4096, 0.4096, 0.1536, 0.0

Zinaida [17]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And if we replace we got:

$E(X) = 0*0.4096 +1*0.4096+ 2*0.1536+ 3*0.0256 +4*0.0016 = 0.8$

So we expect about 0.8 defective computes in a batch of 4 selected.

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

Solution to the problem

For this case we have the following distribution given:

X 0 1 2 3 4

P(X) 0.4096 0.4096 0.1536 0.0256 0.0016

And we satisfy that $P(X_i) \geq 0$ and $\sum P(X_i) =1$ so we have a probability distribution. And we can find the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And if we replace we got:

$E(X) = 0*0.4096 +1*0.4096+ 2*0.1536+ 3*0.0256 +4*0.0016 = 0.8$

So we expect about 0.8 defective computes in a batch of 4 selected.

5 0

4 years ago