The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.
Step-by-step explanation:
Let,
Price of one vegetarian special lunch = x
Price of one chicken special lunch = y
According to given statement;
21x+40y=467 Eqn 1
28x+36y=484 Eqn 2
Multiplying Eqn 1 by 28
Multiplying Eqn 2 by 21
Subtracting Eqn 4 from Eqn 3
Dividing both sides by 364
Putting y=8 in Eqn 1
Dividing both sides by 21
The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.
Keywords: linear equation, elimination method
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