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Svetach [21]
3 years ago
15

Can u guys help me please

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0
1.) 25%
2.) 75%
3.) 25
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Answer: B) f(x)= 1/5 |x|
Used graphic calculator
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3 years ago
Which graph shows the correct solution to the inequality below?
Assoli18 [71]

Answer:

Third Option

Step-by-step explanation:

3x + 18 > 6x - 9

We have to find the value of x for this

Subtract 18 from both sides to leave 3x alone

3x > 6x - 27

Subtract 6x from both sides to be able to find the value of x

-3x > -27

Divide by -3 on both sides

x > 9

The answer would be the third option, since X is anything greater than 9

6 0
3 years ago
Read 2 more answers
Determine the scale factor for each pair of triangles
Alik [6]

Triangle A is the original triangle, and triangle A' is the image.

We need a pair of corresponding sides in the two triangles that are both labeled with lengths.

We see the side labeled 15.2 mm in triangle A', and we see the side labeled 3.8 mm in triangle A. These two sides are corresponding sides.

Divide the length of the side in the image by the length of the side in the original to find the scale factor.

(15.2 mm)/(3.8 mm) = 4

The scale factor is 4.

6 0
3 years ago
I HAVE LIKE 2 MORE QUESTIONS, HELP ME PLZ!
Ne4ueva [31]

Given:

Base length of triangle = 10 units

Height of triangle = \sqrt{44} units

Length of hypotenuse of triangle = 12 units

To find:

Exact value of Cos A

Steps:

The cosine of any angle is equal to the length of the adjacent side by the length of the hypotenuse side.

So,

Cos A = \frac{adjacent}{hypotenuse}

Cos A = \frac{10}{12}

Cos A = 0.833

Therefore, the exact value of cos A is 0.833.

Happy to help :)

If u need any help, feel free to ask

5 0
3 years ago
Please help! I really need it!
amm1812

Answer:

1.  x > 4

2.  m < 2

3.  x > 2

4.  x < -6

Step-by-step explanation:

These 4 inequalities will be solved the same way we solve equations. We take variables to one side and numbers to another and use algebra to solve. Each of them are solved shown below:

1.

4+6x

so x is greater than 4, we can write (variable first):

x > 4

2.

m+16>8m+2\\16-2>8m-m\\14>7m\\\frac{14}{7}>m\\2>m

so m is less than 2, we can write:

m < 2

3.

5x-1>13-2x\\5x+2x>13+1\\7x>14\\x>\frac{14}{7}\\x>2

so x is greater than 2, we can write:

x > 2

4.

-3x-2>-x+10\\-2-10>-x+3x\\-12>2x\\\frac{-12}{2}>x\\-6>x

so x is less than -6, we can write:

x < -6

8 0
3 years ago
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