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nydimaria [60]
3 years ago
12

I really need help with this. I don’t even know where to start um.

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

I don't know that looks hard

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Help me out with this
ArbitrLikvidat [17]

Answer:

What is 2x + 5 (y-1) when x=8 and y=5

Step-by-step explanation:

HELP ME

5 0
3 years ago
Read 2 more answers
Graph the linear function.
nexus9112 [7]
I dont know the awnser sorry
5 0
3 years ago
Jim began a 165 mile bicycle trip to build up stamina for a triathlete competition unfortunately his bike chain broke so he fini
denpristay [2]

Answer: Approximately 4.7 hours.

Step-by-step explanation:

He rode the bicycle for some time before it broke down and he walked the remaining distance. This means that Jim covered a total of 165 miles by riding at a speed of 35 miles per hour and walking at a speed of 3 miles per hour.

Let x = the distance covered by riding the bicycle.

Let y = the distance covered by walking.

Time = distance /speed

Time he used in riding would be x/35

Time he used in walking would be y/3

Since the entire trip took 7 hours,

x/35 + y/3 = 7

3x + 35y = 735 - - - - - - - - 1

Total miles covered is 165. Therefore,

x + y = 165 - - - - - - - - -- - -2

Substituting x = 165-y into equation 1, it becomes

3(165-y) + 35y = 735

495-3y + 35y = 735

-3y + 135y = 735-495

132y = 240

y = 240/132

y = 1.81m

x = 165 - 1.81 = 163.19

Amount of time that he spent on the bicycle will be

x/35 = 163.19/35

= 4.66

Approximately 4.7 hours.

7 0
4 years ago
Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f
Reil [10]

Answer:

\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}

Step-by-step explanation:

The formula of a volume of a square pyramid:

V=\dfrac{1}{3}a^2h

a - base edge

h - height of a pyramid

We have H = 8in.

Substitute and solve for a:

\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}

3 0
3 years ago
Four and two thirds add one and three fourths
Allushta [10]

Answer:

4 2/3 + 1 3/4 = 6 5/12

3 0
3 years ago
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