The probablity that the sample's mean length is greate than 6.3 inches is0.8446.
Given mean of 6.5 inches,standard deviation of 0.5 inches and sample size of 46.
We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.
Probability is the likeliness of happening an event. It lies between 0 and 1. 
Probability is the number of items divided by the total number of items.
We have to use z statistic in this question because the sample size is greater than 30.
μ=6.5
σ=0.5
n=46
z=X-μ/σ
where μ is mean and
σ is standard deviation.
First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.
z=6.3-6.5/0.5
=-0.2/0.5
=-0.4
p value from z table is 0.3446
Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.
Hence the probability that the mean length is greater than 6.3 inches is 0.8446.
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Answer:
1) decay
2) growth
3) growth
Step-by-step explanation:
A generic exponential function can be written as:
f(x) = A*(r)^x
Where:
A is the initial amount of something.
r is the rate of growth.
x is the variable, usually, represents time.
if r > 1, we have an exponential growth.
if r < 1, we have an exponential decay.
1) f(x) = (3/4)^x
in this case we have:
A = 1
r = (3/4) = 0.75
Clearly, r < 1.
Then this is an exponential decay.
2) f(x) = (1/6)*4^x
In this case we have:
A = (1/6)
r = 4
Here we have r > 1.
Then this is an exponential growth.
3) f(x) = (1/4)*(5/2)^x
in this case we have:
A = 1/4
r = 5/2 = 2.5
here we have r > 1, then this is an exponential growth.
 
        
             
        
        
        
La tabla relacionada con la pregunta se puede encontrar en la imagen adjunta a continuación:
Responder:
70%
Explicación paso a paso:
probabilidad de seleccionar aleatoriamente a un participante que haya obtenido entre 71 y 85 puntos:
Probabilidad = resultado requerido / Total de resultados posibles
Resultados posibles totales = Sumando la frecuencia para obtener el número total de estudiantes = (9 + 12 + 12 + 18 + 9) = 60 estudiantes
Resultado requerido:
Clase :
(71 - 75) = frecuencia = 12
(76 - 80) = frecuencia = 12
(81 - 85) = frecuencia = 18
Total = (12 + 12 + 18) = 42 = resultado requerido
Por tanto, P = 42/60 = 0,7 = (0,7 * 100%) = 70%
 
        
             
        
        
        
Answer:
See below for answer.
Step-by-step explanation:
∠ECB ≅ ∠FBC    Parallel lines cut by a transversal form congruent alternate  
                              interior angle  
Δ AEC ≅ Δ DFB   ASA