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2 years ago

What is the y-value to the solution of y = 5x -4 and y = 2x + 8

Mathematics

1 answer:

Fiesta28 [93]2 years ago

6 0

Answer:

At the bottom!

Step-by-step explanation:

Put the two equations into the same standard form:

2x-y=8

-5x+2y=3

Now if you add the two equations up, guess what will happen?

You will "eliminate" the y variable, and only be left with the x variable.

Technically, you will get:

2x-y+2+28-5x+29+2y=8+23

-3x+20y=11

-3x=11

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will got 17 out of 25 questions correct on his driving test what percent correct did he get on the test?

Natalija [7]

Answer:

68%

Step-by-step explanation:

$\frac{17}{25} = \frac{68}{100}$
$\frac{68}{100}$ = 68%

I hope this helps!

5 0

3 years ago

Read 2 more answers

I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th

stellarik [79]

Answer:

The number of once is 9.1

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18 .........1

100 × H + 1 × O = 900 ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴ H = $\frac{882}{99}$

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e O = 18 - 8.9

∴ O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1 and The number of hundreds is 8.9

Answer

4 0

3 years ago

If the area of a triangle is 36 in.^2in.

disa [49]

C. 8 inches. I hope I'm not too late

4 0

2 years ago

Please Help!!<br><br> What should be done 10x ^ 2 - 8x to create a perfect square ?

Pani-rosa [81]

Answer: 10x^2-8x+16

Step-by-step explanation:

Use the formula (b/2)^2

then plug in values:

(-8/2)^2 = -4^2 = 16

ans: 10x^2-8x+16

hope this helps

4 0

2 years ago

If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a

Luba_88 [7]

Answer:

$12C5 *(12C3) = 792*220 =174240 ways$

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

$nCx = \frac{n!}{x! (n-x)!}$

So then 12 C5 would be equal to:

$12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792$

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

$12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220$

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

$(12C5)*(12C3) = 792*220 =174240 ways$

3 0

2 years ago