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Savatey [412]
2 years ago
7

PLEASE HELP ASAPP~ show work

Mathematics
2 answers:
Nastasia [14]2 years ago
6 0

Answer:

D) m=1/2

Step-by-step explanation:

Shalnov [3]2 years ago
4 0
Your supposed to slave for m.
So you put the two points that they give you over each other.
Then you subtract from left to right on top and bottom
Then you’d divid the fraction you end up with
And you get your answer
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Suppose that the probability that your mail is delivered before 2pm is .90. What is the probability that your mail will be deliv
Elden [556K]
1. The probability that your mail is delivered before 2 pm is 0.9, so the probability that the mail is delivered at 2 pm or after 2 pm (so not before 2 pm) is 1-0.9=0.1.

Remark: 0.9=9/10=90/100=90%, and 0.1 is 10%

2. Probability of the mail being delivered before 2 pm for 2 consecutive days is 
\frac{90}{100}*  \frac{90}{100}= \frac{9}{10}*  \frac{9}{10}= \frac{81}{100}=0.81

3. take a look at the picture attached, the tree diagram is another method we could use. 

4 0
3 years ago
M5+m2+m3=180 whays the rwason
Marta_Voda [28]

Answer: 45

Step-by-step explanation: the fub

6 0
3 years ago
The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.
pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

m_{1}\times m_{2}=-1

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

m_{normal} \times m_{tangent}=-1

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

m=\frac{y_2-y_1}{x_2-x_1}

         =\frac{8-4}{-6+6}

          = ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0
3 years ago
The test scores you end up having in geometry class are 81 and 87. What possible scores can you earn on your next test to have a
Zigmanuir [339]

Answer:

88, 89, 90, 91, 92? idrk

4 0
3 years ago
Read 2 more answers
It’s easy please help please please
lions [1.4K]

Step-by-step explanation:

4x - 2y = 8

y = -2

4x -2(-2) = 8

4x + 4 = 8

4x = 4

x = 1

5 0
2 years ago
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