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Dahasolnce [82]

2 years ago

14

Help pls im trying to figure out my money i'm saving for a phone ill give brainliest if u can help. i have $16 rn and on march 1

2th is the 1st day of allowance which is $5 after the end of that week. ill get $5 every week. how long will it take for me to get $303?
i will give brainliest if you help me. pls help

2 answers:

Anni [7]2 years ago

7 0

Answer:

58 weeks.

Step-by-step explanation:

so 303 - 16 you would have 287$ left to earn, then your going to divide it by 5.

it will take you 58 weeks to get to 303$

denis23 [38]2 years ago

5 0

Answer:

It will take you about 58 weeks(14 months) or over one year.

Step-by-step explanation:

<h2>What we Know</h2>

you already have $16

the total amount needed is $303

you get $5 dollars every week

<h2>How To Get The Answer</h2>

1- subtract the total amount needed ($303) from what you already have ($16)

$303 - $16= $287

2- you have to get $287 more dollars to get to $303

3- in order to find out how long it will take you to get to your goal $303 you will divide $287 by the amount you get weekly.

287/5= 57.4 (this will round up to 58)

Therefore It will take you about 58 weeks (14 months) to get to $303

Hope this helps!

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Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of residents 65-years or older who had obtained a flu shot = $\frac{28}{111}$ = 0.25

n = sample of residents 65-years or older = 111

p = population proportion of residents who were getting the flu shot

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

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P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ , $0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ ]

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3 years ago

A ball is tossed between three friends. The first toss is 8.6 feet, the second is 5.8 feet, and the third toss is 7.5 feet, whic

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angles formed by these tosses are $79.45, 59.02$ and $41.53$ degrees to the nearest hundredth.

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The Law of Cosines (also called the Cosine Rule) says:

$c^2 = a^2 + b^2 - 2ab (cosx)$

Using the Cosine Rule to find the measure of the angle opposite the side of length 8.6 feet:

⇒ $c^2 = a^2 + b^2 - 2ab (cosx)$

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The Law of Sines (or Sine Rule) is very useful for solving triangles:

$\frac{a}{sin A} = \frac{ b}{sin B} = \frac{c}{sin C}$

We can now find another angle using the sine rule:

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