Help please please please please

A snail travels at a rate of 2.15 feet per minute . Write a rule to describe the function. b. How far will the snail travel in 7

Jobisdone [24]

15.05 feet in 7 min

2.15 x 7 = 15.05

3 0

2 years ago

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Am solving this problem correct

cestrela7 [59]

A) The degree of the first term is... 1
$first \ term = 3t$
The degree of the second term is... 2
$second \ term = t^2$
The degree of the third term is... 4
$third \ term = t^4$

b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7

c) The degree of the polynomial is... 4

6 0

3 years ago

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Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

Can you help me in my math work

Ket [755]

The LCM of 18 and 24 using the prime-factorization method is 72.

The LCM of 27, 81, and 54, using the division method is 162.

In the first question, we are asked to find the LCM of the given numbers using the prime factorization method.

(i) 18, 24.

Prime factorization gives:

18 = 2*3², and 24 = 2³*3.

The LCM is the product of the highest power of each prime factor.

Thus, LCM = 2³*3² = 8*9 = 72.

Thus, the LCM of 18 and 24 using the prime-factorization method is 72.

Doing similarly for other sub-parts, The LCM of:

(ii) 16, 40 is 80.

(iii) 30, 36 is 180.

(iv) 28, 44 is 308.

(v) 20, 32 is 160.

(vi) 20, 135 is 540.

(vii) 45, 75 is 225.

(viii) 36, 84 is 252.

(ix) 12, 18, 24 is 72.

(x) 25, 35, 45 is 1575.

(xi) 9, 15, 21 is 315.

(xii) 25, 50, 75 is 150.

In the second question, we are asked to find the LCM of the given numbers, using the division method.

(i) 27, 81, 54.

The division method gives:

$\underline{2|27,81,54}\\\underline{3|27,81,27}\\\underline{3|9,27,9}\\\underline {3|3,9,3}\\\underline{3|1,3,1}\\{1|1,1,1}$

The LCM is the product of all the numbers used for division.

LCM = 2*3*3*3*3*1 = 162.

Thus, the LCM of 27, 81, and 54, using the division method is 162.

Doing similarly for other sub-parts, The LCM of:

(ii) 18, 45, 63 is 630.

(iii) 35, 55, 100 is 7700.

(iv) 210, 140, 315 is 1260.

(v) 112, 120, 150 is 8400.

(vi) 144, 180, 300 is 3600.

Learn more about LCM at

brainly.com/question/420337

#SPJ1

7 0

2 years ago

23. Starting with x=0.81818181 , express x as a fraction in simplest form.

White raven [17]

You could do x=81 with the little line on the top (represents the number going on forever, and example is 0.818181818181818181818181818818181818 etc.)

6 0

3 years ago

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