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Y_Kistochka [10]
3 years ago
6

Write a real life scenario that is represented by the integer 15.

Mathematics
1 answer:
ohaa [14]3 years ago
7 0

Answer:

15 buttholes

Step-by-step explanation:

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If y varies inversely as x, and y=16 when x=4, find y when x=10
scoray [572]

Answer:

40

Step-by-step explanation:

you have to multiply x by 4 to get y when x=4 and y=16. so if x=10, then you have to multiply what x is (10) by 4 because there is a common ratio.

hope this helps!! please give brainliest!!!!!!

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3 years ago
Jodi and mariah are sisters. jodi is three years older than mariah. using one variable, write an expression to represent the sum
lapo4ka [179]
Mariah =X
Jodi= X+3

X+X+3= 2X+3
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3 years ago
What is 7/56 simplified
Neko [114]

Answer:

1/8  

Step-by-step explanation:

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3 years ago
Read 2 more answers
Karl is building a rectangular garden bed. The length is 6 feet. She has 20 feet of boards to make the sides. Write and solve an
natali 33 [55]

Answer:

The width of the garden bed must be less than or equal to 4 feet.

w\leq4

Explanation:

Given that;

She has 20 feet of boards to make the sides.

The perimeter of the garden bed must not be more than 20 feet

\begin{gathered} P=2l+2w\leq20 \\ 2l+2w\leq20 \end{gathered}

Given;

The length is 6 feet;

l=6

To get the inequality for the width w, let us substitute the value of the length into the inequality above and simplify;

\begin{gathered} 2l+2w\leq20 \\ 2(6)+2w\leq20 \\ 12+2w\leq20 \\ 2w\leq20-12 \\ 2w\leq8 \\ \frac{2w}{2}\leq\frac{8}{2} \\ w\leq4 \end{gathered}

Therefore, the width of the garden bed must be less than or equal to 4 feet.

w\leq4

8 0
1 year ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Oliga [24]

Answer:

\displaystyle 1)48.2    \:  \: \text{sec}

\rm \displaystyle  2)3021.6 \: m

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

\displaystyle  - 4.9 {t}^{2}  + 229t + 346 = 0

to solve the equation can consider the quadratic formula given by

\displaystyle x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4 ac} }{2a}

so let our a,b and c be -4.9,229 and 346 Thus substitute:

\rm\displaystyle t =  \frac{ - (229) \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

remove parentheses:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

simplify square:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}

simplify multiplication:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 6781.6} }{ - 9.8}

simplify Substraction:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 45659.4} }{ - 9.8}

by simplifying we acquire:

\displaystyle t = 48.2  \:  \:  \: \text{and} \quad  - 1.5

since time can't be negative

\displaystyle t = 48.2

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

\displaystyle x _{  \text{max}} =  \frac{ - b}{2a}

let a and b be -4.9 and 229 respectively thus substitute:

\displaystyle t _{  \text{max}} =  \frac{ - 229}{2( - 4.9)}

simplify which yields:

\displaystyle t _{  \text{max}} =  23.4

now plug in the maximum t to the function:

\rm \displaystyle  h(23.4)- 4.9 {(23.4)}^{2}  + 229(23.4)+ 346

simplify:

\rm \displaystyle  h(23.4)  =  3021.6

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0
3 years ago
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