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Bogdan [553]
3 years ago
9

A chromate ion consists of four oxygen atoms bonded to a chromium atom. It has two extra electrons. The formula of this ion:

Chemistry
2 answers:
Elden [556K]3 years ago
6 0
The formula of this ion is CrO42– . The correct option among all the options that are given in the question is the third option or the last option. The other choices are incorrect and can be easily negated. I hope that this is the answer that you were looking for and the answer has come to your desired help.
Feliz [49]3 years ago
5 0

<u>Answer:</u> The correct answer is CrO_4^{2-}

<u>Explanation:</u>

Chromate ion is formed by the combination of one chromium atom and four oxygen atoms. The ion formed has two more electrons.

An ion which has extra electrons carries a negative charge on them and the ion which has more electrons carries a positive charge on them.

As, chromate ions have 2 extra electrons, Thus, it carries a charge of -2.

Hence, the correct answer is CrO_4^{2-}

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Please help me thank you.
Semmy [17]
I will show you with detailed work for NaCl, but follow the same procedure for the rest of the compounds.

Molar Mass - Find the molar mass of the Na and the Cl and add them together
Na - 23
Cl - 35.5
Add those numbers together 23 + 35.5 = 58.5 g/mol

Moles in 1 tsp:
The mass measured in 1tsp of NaCl was 18 g.  To calculate the amount of moles you take the mass measured and divide it by the molecular weight.
18/58.5 = 0.3077 mol

Moles of each element:
To find the moles each element in the compound you multiply the moles of 1 tsp by the number of atoms of the element in the compound
Na - 1 in NaCl
Cl - 1 in Na Cl
so take 0.3077 * 1 = 0.3077 moles Na (and Cl in this case)

Atoms of each:
take the number of moles calculated and multiply that by Avogadro's number(6.023x10^23) for the number of molecules
So for both Na and Cl:
0.3077 * 6.023x10^23 = 1.853x10^23 atoms for both Na and Cl
7 0
4 years ago
Balance <br> Si4H10+O2&gt;SiO2+H2O
Illusion [34]

Explanation: Si4H10+O2>SiO2+H2O

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5 0
3 years ago
How many grams of sodium hydroxide are needed to make 500mLs of a 0.125M NaOH solution?
dybincka [34]
need 0.500 x 0.125 = 0.0625 moles of NaOH. The molecular weight is 23+16+1 = 40, so 0.0625 x 40 = 2.5 grams will do the trick.
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Explanation:

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