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aniked [119]
3 years ago
8

Aspirin synthesis involves the addition of an acetyl group to salicylic acid in a condensation reaction with an alcohol. The ace

tyl group could be added with a carboxylic acid but the preferred procedure is to use the acid anhydride. Why is preferable to use an acid anhydride for ester formation with an alcohol rather than a carboxylic acid? Select one: Carboxylic acids react with water in an undesired side reaction. Acid anhydrides are generally easier and safer to handle than carboxylic acids. Carboxylic acids change the pH of the solution too much for the reaction to proceed. Acid anhydrides are less stable than esters so the equilibrium favors the ester product.
Chemistry
1 answer:
BARSIC [14]3 years ago
3 0

Answer:

The correct appropriate will be Option 1 (Acid anhydrides are less stable than esters so the equilibrium favors the ester product.)

Explanation:

  • Acid anhydride, instead of just a carboxyl group, is typically favored for esterification. The predominant theory would be that Anhydride acid is somewhat more volatile than acid. This is favored equilibrium changes more toward the right of the whole ester structure.
  • Extremely responsive than carboxylic acid become acid anhydride as well as acyl chloride. Thus, for esterification, individuals were most favored.

The other options offered are not relevant to something like the scenario presented. So, the solution here is just the right one.

You might be interested in
38. Identify the most important types of interparticle forces pres
zhannawk [14.2K]

Answer: im thinking its gonna be d.C2H6 and also

the explanation is on the research i had did before i had answered this question so i really hope this help :)

Explanation:

Ar = van de waals forces or london forces

C

H

4

= van de waals forces or london forces

HCl=permanent dipole-dipole interactions

CO = permanent dipole-dipole interactions

HF = hydrogen bonding

N

a

N

O

3

= permanent dipole-dipole interactions

C

a

C

l

2

= van de waals forces or london forces

4 0
3 years ago
Imagine the movement of a single gas molecule inside a container. Explain the particles motions in terms of kinetic- molecular t
Nikitich [7]

Answer:

we know that gas molecules move fast by hitting the container and they never meet,so if we have one single gas molecule then it will move slower . This is because it is alone in an empty container so until it hits the container to change it's movements it will make the process slower.

Read the explanation below to have a better idea based on the kinetic molecular theory.

Explanation:

Hello in this question we have a container and in it is a single gas molecule. So there is our gas molecule and in fact right there that violates the kinetic molecular theory. Because the kinetic molecular theory thinks of these particles as being dimension less points. Because there is so much space between particles. The particles themselves have such an insignificant volume as they can be thought of as dimension lys points. Okay. But anyway this particle is in rapid motion and this motion is essentially random. So it's moving and it will eventually hit the wall of its container. It's moving rapidly so it's going to hit it pretty quickly and when it hits the wall of that container Yeah, it is going to bounce off when it does that. It's a totally elastic collision. So that means there will be no energy transfer, no energy loss, no energy gained. It will just serve to change the direction of the particle. So when it hits the wall it's going to bounce back off the wall and continue in a straight line until it hits another wall and then it will bounce off that wall and it will continue moving in this motion in this motion its speed is related to the amount of energy it has and therefore its temperature. So if we add heat, it will move faster. If we remove heat or cool it down, it will move slower. So when we remove heat, it will move slower. The kinetic molecular theory says it will be constantly moving As long as it is above absolute zero. It's only at absolute zero or 0 Kelvin, where would stop moving. Okay, so all these things describe its motion. It's in rapid random motion in a straight line until it hits the wall of its container. Then it will rebound without a transfer of any energy. It will be totally elastic collision. If we were to heat it up, it would move faster. If we were to cool it down, it would move more slowly, we would have to cool it all the way down to absolute zero before it would stop moving. Right, so all of these things describe its motion. In terms of that kinetic molecular theory,

5 0
2 years ago
Which are the hybrid orbitals of the carbon atoms in the following molecules? (a) H3C―CH3 sp sp2 sp3 (b) H3C―CH═CH2 sp sp2 sp3 (
kherson [118]

Answer:

(a)  sp³    sp³

   H₃<u>C</u> - <u>C</u>H₃

(b)     sp³           sp²

     H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂

                sp²

(c)     sp³        sp    

    H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH

              sp         sp³

(d)     sp³    sp²    

       H₃<u>C</u> - <u>C</u>H=O

Explanation:

Alkanes or the carbons with all the single bonds are sp³ hybridized.

Alkenes or the carbons with double bond(s) are sp² hybridized.

Alkynes or the carbons with triple bond are sp hybridized.

Considering:

(a) H₃C-CH₃ , Both the carbons are bonded by single bond so both the carbons are sp³ hybridized.

Hence,

 sp³    sp³

H₃<u>C</u> - <u>C</u>H₃

(b) H₃C-CH=CH₂ , The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp² hybridized because they are bonded by double bond.

Hence,

   sp³           sp²

H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂

         sp²

(c) H₃C-C≡C-CH₂OH , The carbons of the methyl group and alcoholic group are sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp hybridized because they are bonded by triple bond.

Hence,

   sp³        sp    

H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH

         sp         sp³

(d)CH₃CH=O, The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The other carbon is sp² hybridized because it is  bonded by double bond to oxygen.

Hence,

   sp³    sp²    

 H₃<u>C</u> - <u>C</u>H=O

     

8 0
3 years ago
How many molecules are there in 5.0g of C2H5OH?
Vilka [71]
About 6.5x10^22 molecules. (5g C2H5OH)x(1 mol C2H5OH/46g C2H5OH)x(6.02x10^23 molecules C2H5OH/1 mol C2H5OH)=(3.01E24)/46=6.5x10^22. Let me know if this helped!
4 0
3 years ago
The smallest volume from among the following is
dem82 [27]
If it is multiple choice the answer is <span>C. 0.012 L.</span>
6 0
3 years ago
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