1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ioda
2 years ago
12

Kendal has a 5-pound bag of flour that holds 1812 cups.

Mathematics
1 answer:
defon2 years ago
6 0

Answer:

1812 - 5 (314)

Step-by-step explanation:

The total is 1812 and Kendal is subtracting 5 314s from that total. You just have to multiply 5 times 314 and subtract that from 1812.

You might be interested in
___ cosb =1/2 sin(a+b)+sin(a-b)?
vodomira [7]

Answer:

That would be sina.

Step-by-step explanation:

sin(a+b) = sinacosb + cosasinb

sin(a-b) = sinacosb -  cosasinb

Adding we get  sin(a+b) + sin(a-b) = 2sinaccosb

so sinacosb = 1/2sin(a+b) + sin(a-b)

8 0
3 years ago
Read 2 more answers
If sally wants to have 400 square yards of carpet installed which company would be cheaper?
Nina [5.8K]

Answer: country carpets are cheaper

Step-by-step explanation:

6 0
2 years ago
What is the answer plz help
atroni [7]

Answer:

108

Step-by-step explanation:

12/4=3

36 x 3 = 108

3 0
3 years ago
Solve the following equation algebraically<br>4x^2 = 100​
Licemer1 [7]

Answer:

x  = ±5

Step-by-step explanation:

4x^2 = 100​

Divide each side by 4

4/4x^2 = 100/4

x^2 = 25

Take the square root of each side

​sqrt(x^2) = ±sqrt(25)

x  = ±5

7 0
2 years ago
Find the sum of the series Summation from n equals 1 to infinity (StartFraction 3 Over StartRoot n plus 2 EndRoot EndFraction mi
Marizza181 [45]

Looks like the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}

The series telescopes; consider the kth partial sum of the series,

S_k=\displaystyle\sum_{n=1}^k\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}

S_k=\displaystyle\left(\frac3{\sqrt3}-\frac32\right)+\left(\frac32-\frac3{\sqrt5}\right)+\cdots+\left(\frac3{\sqrt{k+1}}-\frac3{\sqrt{k+2}}\right)+\left(\frac3{\sqrt{k+2}}-\frac3{\sqrt{k+3}}\right)

\implies S_k=\dfrac3{\sqrt3}-\dfrac3{\sqrt{k+3}}

As k\to\infty, the second term converges to 0, leaving us with

\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}=\frac3{\sqrt3}=\boxed{\sqrt3}}

7 0
3 years ago
Other questions:
  • Need this answer fast!! help!!!
    14·1 answer
  • 8/3 + 3/4 equals...
    6·2 answers
  • The stem-and-leaf plot. represents the number of flowers in different public gardens throughout the city. How many gardens have
    5·1 answer
  • a building 62 feet tall costs a shadow 21 meters long at what angle is the sun shining on the building
    11·1 answer
  • Help please what is the sum of the series ?
    10·1 answer
  • A cylinder with radius 3 meters and height 7 meters has its radius tripled. How many times greater is the volume of the larger c
    8·1 answer
  • Someone help pls :((
    12·1 answer
  • Help me please help please
    12·2 answers
  • Simplify a-c when a=5,c=-1​
    5·1 answer
  • In 8 divided by 1/5 the number 8 is the?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!