784 in^3 because you break up the two shapes and add them together
The first one, I'm not sure how to prove that, but for the other three the graphs clearly coincide if you draw them.
Answer:
The require gradient is 3/5
Step-by-step explanation:
y(x) = 5x/(2x^2+4).................(1)
y(sqrt(3)) = sqrt(3)/2 => (sqrt(3), sqrt(3)/2) is a point on the curve of (1)
differentiate y(x) with respect to x using the quotient rule to get
y'(x) = 20x^2/(2x^2+4)^2 ................(2)
substitute x = (sqrt(3), sqrt(3)/2) in (2)
y'(sqrt(3))
= 20(sqrt(3))^2 / (2(sqrt(3))^2 + 4)^2
= 20*3 / (10)^2
= 60 / 100
= 3/5
The diagonal of square is a√2
the half of it a√2/2=12
a=12*2/√2=12√2
S=a^2=12√2*12√2=288
Answer:
1/4 ; 3/8
Step-by-step explanation:
Probability of landing on 2 :
Required outcome = Number of 2's on spinner = 2
Total possible outcomes = Number of congruent spaces on spinner = 8
P(landing on a 2) = 2 / 8 = 1/4
Probability of landing on 1 :
Required outcome = Number of 1's on spinner = 3
Total possible outcomes = Number of congruent spaces on spinner = 8
P(landing on a 1) = 3 / 8
Landing in each section of the spinner is equally likely to occur as the spinner are divided into congruent spaces. However, landing on the labels of the spinner isn't equally likely as each label take up uneven number of congruent spaces on the spinner.