All categories

3 years ago

Solve 15 ≥ -3x or x ≥ -2. {x | x ≤ -5} {x | x ≥ -5} {all reals}

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

8 0

The correct option would be:

{x | x ≥ -5}

I had this same question on a test and I got it right.

diamong [38]3 years ago

7 0

Answer:

I do not quite understand, but i will give it my best shot. 15 <u>></u> -15.

Step-by-step explanation:

You might be interested in

ILL MARKE BRAINLIEST IF YOU SHOW YOUR WORK

madam [21]

The function of the relationship above is y=5x+4

4 0

4 years ago

Find the most important variable in the problem.

natali 33 [55]

Answer:

Step-by-step explanation:

Let

x = the number of phone available

If it would require 8 more phones, then the total number of phones will be x + 8.

A company hired an additional 12 employees, and every employee needed a phone, then

x + 8 = 12

x = 4

This means 4 phones were available (and 8 more needed to total in 12 phones for 12 new employees)

Hence, correct option is option A.

3 0

4 years ago

Classify each triangle by its sides.

Free_Kalibri [48]

Answer:

Step-by-step explanation:

None of the sides are equal. Isosceles means that 2 sides are equal. Equilateral means that all sides are equal.

3 0

3 years ago

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

8 0

3 years ago

Simplify(4-x) (7+x) <br>

Sophie [7]

(4-x) ( 7+ ×)

28 +4x -7x -x²

28 -3x - x²

7 0

3 years ago