Find the median of the following data set 6,2,59,12,11,9,9,54,54,46,2,32,43,11
Aleonysh [2.5K]
By arranging the numbers in ascending order we get,
2, 2, 6, 9, 9, 11, 11, 12, 32, 43, 46, 54, 54, 59
The 2 middle numbers are:
11, 12
To find the median we have to add them and divide them by 2
So, (11+12)÷2
23÷2
11.5
Answer:
The answer is D
That's the only equation will get us one point
Step One
Find the base area of the large hexagon as though the smaller one was not removed.
Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.
Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)
Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.
Area of the remaining piece = area of large hexagon - area of the small hexagon
Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)
Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18
I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3
First you subtract (1/4) from each side to get C by itself, then you convert (4/4) into 1. Then you divide both sides by (-4) to get C to equal 1. So your final answer is C=-1/4
Answer(s):
31:
4.5 = 4 + 1/2 (0.5)
32:
23.7 = 20 + 3 + 7/10 (0.7)
33:
6.9 = 6 + 0.9
34:
35.4 = 30 + 5 + 0.4
it's kinda implied :)
Good Luck Dude.
