Answer:
Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.
One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.
Then,
The number of Barr bodies with Klinefelter would be:
Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.
Similarly, for
Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)
Now, as per the question, the bar bodies for karyotypes given
47,XYY: (n-1) = (1-1) = 0 Barr bodies
47,XXX: (n-1) = (3-1) = 2 Barr bodies
48,XXXX: (n-1) = (4-1) = 3 Barr bodies
