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sergey [27]
3 years ago
9

Help and I'll give someone brainliest simplify (a^-2b^2/a^2b^-1)^-3

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

\frac{a12}{b3}

Step-by-step explanation:

Hope this is right and helps you!

natka813 [3]3 years ago
6 0

Answer:

a^12/b^9

Step-by-step explanation:

You need to multiply the exponent -3 to every other exponent

So then you would end up with a^6b^-6/a^-6b^3

Now you need to flip the negative exponents to the other side which would be a^12/b^9

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Answer:

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Step-by-step explanation:

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    \sf \text{The reciprocal of any number $\dfrac{a}{b}$ is given by $\dfrac{b}{a}$}\\\\5\dfrac{1}{2}=\dfrac{11}{2}\\\\\text{Reciprocal of $\dfrac{11}{2}$  = $\dfrac{2}{11}$}

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 \text{Additive inverse of $\dfrac{-7}{8}$=$\dfrac{7}{8}$}

        Now multiply,

          \sf \dfrac{7}{8}*\dfrac{2}{11}=\dfrac{7}{4}*\dfrac{1}{11}\\

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