Question

Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)​PLEASE HELP!

Answer 1

Answer:

$\bold { \dfrac{7}{44} }$

Step-by-step explanation:

Reciprocal:

    $\sf \text{The reciprocal of any number \dfrac{a}{b} is given by \dfrac{b}{a} }\\\\5\dfrac{1}{2}=\dfrac{11}{2}\\\\\text{Reciprocal of \dfrac{11}{2} = \dfrac{2}{11} }$

Additive inverse:

 $\text{Additive inverse of \dfrac{-7}{8} = \dfrac{7}{8} }$

        Now multiply,

          $\sf \dfrac{7}{8}*\dfrac{2}{11}=\dfrac{7}{4}*\dfrac{1}{11}$

                      $=\dfrac{7}{44}$