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2 years ago

Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)PLEASE HELP!

Mathematics

1 answer:

EleoNora [17]2 years ago

7 0

Answer:

$\bold {$\dfrac{7}{44}$}$

Step-by-step explanation:

<h3> Reciprocal:</h3>

$\sf \text{The reciprocal of any number $\dfrac{a}{b}$ is given by $\dfrac{b}{a}$}\\\\5\dfrac{1}{2}=\dfrac{11}{2}\\\\\text{Reciprocal of $\dfrac{11}{2}$ = $\dfrac{2}{11}$}$

<h3>Additive inverse:</h3>

$\text{Additive inverse of $\dfrac{-7}{8}$=$\dfrac{7}{8}$}$

Now multiply,

$\sf \dfrac{7}{8}*\dfrac{2}{11}=\dfrac{7}{4}*\dfrac{1}{11}\\$

$=\dfrac{7}{44}$

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3 years ago

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For this next integral, we rewrite the integrand

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3 years ago

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Answer and Step-by-step explanation:

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3 years ago

Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)​PLEASE HELP!

Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)PLEASE HELP!