3 years ago

PLEASE HELP WITH MATH QUESTION !!! ( WILL MARK BRAINLIEST )

Mathematics

1 answer:

rosijanka [135]3 years ago

8 0

Answer:

any figure is given?? I think so

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kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

$\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\$

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence $lnv = -2t+ln 7\\v=7e^{-2t}$

since velocity is rate of change of distance s we have

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substitute t=0 and s=0

$C=7/2$

So solution for distance is

$s(t) =\frac{-7}{2} (e^{-2t}-1)$

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